Question #e7870

1 Answer
Jan 12, 2018

37/42

Explanation:

Let's find the opposite outcome: what's the probability that no vowels are chosen?

Well, BREAKDOWN has 9 letters, and 6 are consonants. The probability that the first letter chosen being a consonant is 6//9.

Now assume we choose a second letter. We have left only 8 letters now, and since we already chose a consonant, only 5 consonants are left. The probability of picking a second consonant is 5//8.

Using the same logic, the probability of choosing a third consonant is 4//7 and a fourth consonant is 3//6.

So, the probability of choosing all 4 letters that are all consonants is:

6/9(5/8)(4/7)(3/6)

Simplifying...

=2/3(5/8)(4/7)(1/2)=5/42

What we want, however, is the case where at least 1 vowel is selected. This has zero overlap with the case we found, where 0 vowels are selected.

Thus, the probability we are looking for is:

1-5/42=37/42