Given the %mass of the solution and the mass of the solution, mass of solute can be computed as;
"%mass solution"="mass solute"/"mass solution"%mass solution=mass solutemass solution
"mass solute"="%mass solution" xx "mass solution"mass solute=%mass solution×mass solution
"mass solute"=0.30xx250g=75gmass solute=0.30×250g=75g
Then, find the mass of the solvent, knowing that;
"mass solution"="mass solute"+"mass solvent"mass solution=mass solute+mass solvent
"mass solvent"="mass solution"-"mass solute"mass solvent=mass solution−mass solute
"mass solvent"=250g-75g=175gmass solvent=250g−75g=175g
Now, find the volume of the solvent; knowing that the density of water @ 4^oC4oC= 1g/ml; so that,
rho=m/Vρ=mV
V=m/rhoV=mρ
V=(175cancel(g))/((1cancel(g))/(ml))
V=175ml