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Question #f0136

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Jan 14, 2018

$m_{neutron} \approx 1.0093872 amu$ $m_"neutron"~~1.0093872 "amu"$

Explanation:

Well, an electron weighs around $0.00054858 amu$ $0.00054858 "amu"$ , and if a neutron weighs $1840$ $1840$ times the mass of an electron, then

$m_{neutron} = 1840 \cdot 0.00054858 = 1.0093872 amu$ $m_"neutron"=1840*0.00054858=1.0093872 "amu"$

However, the real mass of a neutron is around $1.00864 amu$ $1.00864 "amu"$ .

Source:

http://physics.bu.edu/~duffy/sc546_notes10/mass_defect.html

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