Question #7ad24

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Answer 1 · 2018-01-14T16:49:27

$Details are shown below.$ $"Details are shown below."$

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$A_{x} = A . cos θ$ $A_x= A .cos theta$

$- 20 = A . cos (130)$ $-20=A. cos (130)$

$cos (130) = - cos (50) = - 0.64278761$ $cos(130)=-cos (50)=-0.64278761$

$- 20 = A . (- 0.64278761)$ $-20=A .(-0.64278761)$

$A = \frac{- 20}{- 0.64278761}$ $A=(-20)/(-0.64278761)$

$A = 31.11 units$ $A=31.11" units"$

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$cos (40) = sin (50) = 0.76604444$ $cos(40)=sin(50)=0.76604444$

$A_{y} = A . cos (40) = 31.11 \cdot 0.76604444$ $A_y=A. cos(40)=31.11*0.76604444$

$A_{y} = 31.11 \cdot 0.76604444$ $A_y=31.11*0.76604444$

$A_{y} = 23.83 units$ $A_y=23.83" units"$