What is the domain and range of #y=1/(x-1)^2#? Algebra Expressions, Equations, and Functions Domain and Range of a Function 1 Answer turksvids Jan 15, 2018 Domain: #x in RR#, #x ne 1#. Range: #y>0# Explanation: The graph of #y=1/x^2# has domain #x in RR#, #x ne 0# and #y>0#. #y=1/(x-1)^2# is a horizontal shift of 1 unit to the right, so the new domain is #x in RR#, #x ne 1#. The range does not change, so it's still #y>0#. Answer link Related questions How do you determine if (-1, 4), (2, 8), (-1, 5) is a function? What is the domain for #f(x)=2x-4#? What is the domain and range for (3,1), (1,-4), and (2, 8)? What is the domain and range of a linear function? Is domain the independent or dependent variable? How do you find the domain and range of a function in interval notation? How do you find domain and range of a rational function? How do you find domain and range of a quadratic function? How do you determine the domain and range of a function? What is Domain and Range of a Function? See all questions in Domain and Range of a Function Impact of this question 5360 views around the world You can reuse this answer Creative Commons License