Question #39aec

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Question #39aec

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Answer 1 · 2018-01-15T21:49:28

$T_{2} = ? K$ $T_2=?K$

Explanation:

This can be solved using the combined gas law where $η$ $eta$ is constant; thus, the formula

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ $(P_1V_1)/(T_1)=(P_2V_2)/(T_2)$

Identify the given and the unknown data and the solving process to find the required variable as follows: ( Note: Temperature must be expressed in K)

$G i v e n :$ $Given:$
$V_{1} = 2.9 L$ $V_1=2.9L$
$P_{1} = 5.0 a t m$ $P_1=5.0 atm$
$T_{1} = 50^{o} C + 273 = 323 K$ $T_1=50^oC+273=323K$
$V_{2} = 2.4 L$ $V_2=2.4L$
$P_{2} = 3.0 a t m$ $P_2=3.0 atm$

, $R e q u i r e d :$ $Required:$
$T_{2} = ?$ $T_2=?$

$S o l u t i o n :$ $Solution:$
Start with the formula. Rearrange it as needed to isolate the required variable and plug in data as identified earlier; that is,
$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ $(P_1V_1)/(T_1)=(P_2V_2)/(T_2)$
$T_{2} = \frac{T_{1} P_{2} V_{2}}{P_{1} V_{1}}$ $T_2=(T_1P_2V_2)/(P_1V_1)$
$T_{2} = ? K$ $T_2=?K$

Note: Do not forget to attach the unit of each variable; cancel as needed to get the desired unit which is K.

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Question #39aec

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