How do you differentiate #x^-7 - 7x^-1#? Calculus Basic Differentiation Rules Power Rule 1 Answer David C. Jan 16, 2018 #-7x^-8+7x^-2# Explanation: Let #y=x^-7-7x^-1# #y'=(x^-7)'-(7x^-1)'# By the power rule #(x^n)'=nx^(n-1)# we get: #y'=-7x^(-7-1)-7times(-1x^(-1-1))# By simplifying, we get: #-7x^-8+7x^-2# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 1619 views around the world You can reuse this answer Creative Commons License