Question #3dbe1

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Question #3dbe1

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Answer 1 · 2018-01-18T21:21:18

$a . \approx 183 m l$ $a. ~~183ml$
$b . \approx 260 g$ $b. ~~260g$

Explanation:

A. Assuming that the concentration of the solution presented is in %w/w; thus the formula shown below is applicable to solve this problem.

$% s o l u t i o n (\frac{w}{w}) = \frac{mass solute (m)}{mass solution (m_{s})}$ $%solution(w/w)=("mass solute"(m))/("mass solution"(m_s))$
where:

$% s o l u t i o n = 17 %$ $% solution =17%$
$mass solute = 35 g N a C l$ $"mass solute"=35gNaCl$
$ρ solution = \frac{1.13 g}{c m^{3}}$ $rho " solution"=(1.13g)/(cm^3)$

Now, plug in given data to its respective variable to get the intermediate value needed to solve the prescribed problem. Rearrange formula as needed to isolate the required variable; that is,

$% s o l u t i o n (\frac{w}{w}) = \frac{m}{m_{s}}$ $%solution(w/w)=m/m_s$
$m_{s} = \frac{m}{% s o l u t i o n}$ $m_s=(m)/(%solution)$
$m_{s} = \frac{35 g}{0.17}$ $m_s=(35g)/(0.17)$
$m_{s} = 205.8824 g$ $m_s=205.8824g$

Knowing the $m_{s}$ $m_s$ , the total volume of the solution that also contained the given mass of the solute can be calculated through the density formula; thus,

$ρ_{s} = \frac{m_{s}}{V_{s}}$ $rho_s=m_s/V_s$
where:

$ρ_{s} = density of the solution$ $rho_s="density of the solution"$
$m_{s} = mass of the solution$ $m_s="mass of the solution"$
$V_{s} = volume of the solution$ $V_s="volume of the solution"$

$V_{s} = \frac{m_{s}}{ρ_{s}}$ $V_s=m_s/rho_s$
$V_s=(205.8824cancel(g))/((1.13cancel(g))/(ml))$
$V_s~~183ml$

B. Assuming that the concentration of the solution presented is again in %w/w; thus the formula shown below is applicable to solve this problem.

$%solution(w/w)=("mass solute"(m))/("mass solution"(m_s))$
where:

$% solution =58%$
$"mass solute"=150g H_2SO_4$

Now, plug in given data to its respective variable to get the intermediate value needed to solve the prescribed problem. Rearrange formula as needed to isolate the required variable; that is,

$%solution(w/w)=m/m_s$
$m_s=(m)/(%solution)$
$m_s=(150g)/(0.58)$
$m_s=260g$

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Question #3dbe1

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