How do you solve $16 - 2 c = - 20 - 20 c$ $16- 2c = - 20- 20c$ ?

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Answer 1 · 2018-01-20T03:22:48

$c = - 2$ $c = -2$

Begin with the equation

$16 - 2 c = - 20 - 20 c$ $16 - 2c = -20 -20c$

Use the additive inverse to move the terms with the variables to the same side

$16 - 2c + 20c = -20 cancel(-20c) cancel (+20c)$

$16 + 18c = -20$

Use the additive inverse to move the constant terms to the same side

$cancel16 + 18c cancel(-16)= -20 -16$

$18c = -36$

Use the multiplicative inverse to isolate the variable

$(cancel(18)c)/cancel(18) = (-36)/18$

Solution $c = -2$ .

How do you solve 16- 2c = - 20- 20c16−2c=−20−20c16- 2c = - 20- 20c?