How do you simplify $(t^{2} - 5 t - 4) + (2 t^{2} - 7 t + 6)$ $(t ^ { 2} - 5t - 4) + ( 2t ^ { 2} - 7t + 6)$ ?

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How do you simplify $(t^{2} - 5 t - 4) + (2 t^{2} - 7 t + 6)$ $(t ^ { 2} - 5t - 4) + ( 2t ^ { 2} - 7t + 6)$ ?

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Answer 1 · 2018-01-20T05:44:40

$3 t^{2} - 12 t + 2$ $3t^2-12t+2$

Explanation:

$(t^{2} - 5 t - 4) + (2 t^{2} - 7 t + 6)$ $(t^2-5t-4)+(2t^2-7t+6)$
is the same as:
$t^{2} - 5 t - 4 + 2 t^{2} - 7 t + 6$ $t^2-5t-4+2t^2-7t+6$
This becomes, once reordered:
$t^{2} + 2 t^{2} - 5 t - 7 t - 4 + 6$ $t^2+2t^2-5t-7t-4+6$
Combine the like terms:
$3 t^{2} - 12 t + 2$ $3t^2-12t+2$

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How do you simplify $(t^{2} - 5 t - 4) + (2 t^{2} - 7 t + 6)$ $(t ^ { 2} - 5t - 4) + ( 2t ^ { 2} - 7t + 6)$ ?

1 Answer

Explanation:

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Science

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How do you simplify (t2−5t−4)+(2t2−7t+6)(t ^ { 2} - 5t - 4) + ( 2t ^ { 2} - 7t + 6)?

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Explanation:

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How do you simplify $(t^{2} - 5 t - 4) + (2 t^{2} - 7 t + 6)$ $(t ^ { 2} - 5t - 4) + ( 2t ^ { 2} - 7t + 6)$ ?