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Answer 1 · 2018-01-21T16:09:18

#x=3#

![my http://notebook...](https://useruploads.socratic.org/9IPPMn1VSwK6r97uN51s_New%20Doc%202018-01-21%20%282%29_1.jpg)

Hope it helps....
Thank you...

Answer 2 · 2018-01-21T16:48:20

#x=3#

#3/(1+2^(2-x))=2#

#3=2+2*2^(2-x)#

#1=2^1*2^(2-x)#

#1=2^(2-x+1)#

#1=2^(3-x)#

#ln1=ln2^(3-x)#

#(3-x)ln2=0#

#3ln2-xln2=0#

#xln2=3ln2#

#x=3#