How do you simplify $\frac{1}{\frac{{(- 2 b^{- 2})}^{- 4}}{3 c^{3}}}$ $\frac { 1} { \frac (( - 2b ^ { - 2}) ^-4) { 3c ^ { 3} } }$ ?

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Answer 1 · 2018-01-22T02:28:03

$\frac{48 c^{3}}{b^{8}}$ $(48c^3)/b^8$

I made a video explaining how I went about simplifying this algebraic expression.

I hope it helps :)

Harold

How do you simplify 1(−2b−2)−43c3\frac { 1} { \frac (( - 2b ^ { - 2}) ^-4) { 3c ^ { 3} } }?