What is the derivative of # x^2/3 - 3/x^2#?

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Answer 1 · 2018-01-22T03:13:57

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Answer 2 · 2018-01-22T03:21:02

#f'(x)=(2x)/3+6/(x^3)#

Given: #f(x)=x^2/3-3/x^2#

#f'(x)=1/3d/dx[x^2]-3d/dx[1/x^2]#

#d/dx[x^2]=2x#

#d/dx[1/x^2]=>d/dx[x^-2]=-2x^(-2-1)=-2x^(-3)=-2/(x^3)#

#f'(x)=1/3*2x-3*-2/(x^3)=(2x)/3+6/(x^3)#