Question

Two charges of `9 C` and `-8 C` are positioned on a line at points `-3` and `-1`, respectively. What is the net force on a charge of `7 C` at `0`?

Answer 1

`441×10^9 N`

Explanation:

Here,the `9C` charge tries to push the `7C` charge towards positive direction.

And the value of that force `F1` is
`(9×10^9)×9×7/(3)^2 N` i.e `63×10^9 N`

Whereas, the `-8C` charge tries to pull the `7C` charge towards its position i.e in negative direction.

And the amount of force `F2` is
`(9×10^9)×(-8)×7/(-1)^2 N` or,`504×10^9 N`

So,net force acting is towards negative direction and it is `F2 - F1` i.e `(504-63)×10^9 N` or, `441×10^9 N`