How do you divide $\frac { 6p ^ { 2} } { 9^ { 4} } \div \frac { 3} { 2p }$ ?

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Answer 1 · 2018-01-23T03:53:13

Use the reciprocal rule $a/b\div c/d$ $=$ $a/b \times d/c$ to invert the divisor fraction and then evaluate.

So, by following the concept provided above, we get:

$=\frac{6p^2}{9^4}\times \frac{2p}{3}$

Simplify by yourself applying the exponent rules,

$=\frac{4p^3}{6561}$

How do you divide \frac { 6p ^ { 2} } { 9^ { 4} } \div \frac { 3} { 2p }\frac { 6p ^ { 2} } { 9^ { 4} } \div \frac { 3} { 2p }?