Question

Question #47e8d

Answer 1

28%

Explanation:

If The temperature is 100,
`100` decreased by `60%=40` Degrees
`80% of 40: 32`
`40+32=72`
`100-72=28`
`28%`

Answer 2

See a solution process below:

Explanation:

First, let's call the initial temperature: `t`

If it first decreased by 60% then the new temperature (`t_n`) would be:

`t_n = t - 60/100t`

`t_n = 100/100t - 60/100t`

`t_n = (100/100 - 60/100)t`

`t_n = 40/100t`

`t_n = 4/10t`

Then if this new temperature increase by 80% the final temperature (`t_f`) would be:

`t_f = t_n + 80/100t_n`

However, we can substitute `4/10t` for `t_n` giving:

`t_f = 4/10t + (80/100 xx 4/10t)`

`t_f = 4/10t + 320/1000t`

`t_f = 400/1000t + 320/1000t`

`t_f = 720/1000t`

`t_f = 72/100t`

Therefore, the final temperature is 72% of the original temperature.

Or, in total the temperature decreased by 28%