How do you combine $\frac { 3} { 2h ^ { 2} - 2h } + \frac { 5} { 2h - 2}$ ?

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Answer 1 · 2018-01-24T02:03:01

$(3+5h) / (2h^2+h)$

Your equation can be factored like this.
$3/(h(2h-2)) + 5/(2h-2)$

$1/(2h-2) * (3/h + 5)$

$(3+5h) / h * 1/(2h-2)$

$(3+5h) / (2h^2+h)$ is the simpliest form.

How do you combine \frac { 3} { 2h ^ { 2} - 2h } + \frac { 5} { 2h - 2}\frac { 3} { 2h ^ { 2} - 2h } + \frac { 5} { 2h - 2}?