How do you solve this physics problem ?
there are two A and B balls on a pool table at rest, one next to the other. After the impulse, the A-ball moves with an
acceleration of 12 m/s^2 and the B ball with an acceleration of 24 m/s^2. If the angle formed between the two balls is 60°, what will be the distance, in cm, between the two balls after one second, considering that neither of them has fallen into the hole?
THANK YOU
there are two A and B balls on a pool table at rest, one next to the other. After the impulse, the A-ball moves with an
acceleration of 12 m/s^2 and the B ball with an acceleration of 24 m/s^2. If the angle formed between the two balls is 60°, what will be the distance, in cm, between the two balls after one second, considering that neither of them has fallen into the hole?
THANK YOU
1 Answer
First we find the distance covered by each ball, then the distance between them. They are
Explanation:
For both balls, the initial velocity
reduces to:
For Ball A:
For Ball B:
We can't simply subtract one from the other, though, because they are at a
Take the square root of both sides:
We were asked for the answer in
(side note: this is clearly not a standard size pool or billiard table!)