How do you solve $- 5 (5 + 4 a) = 115$ $-5( 5+ 4a ) = 115$ ?

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Answer 1 · 2018-01-25T03:05:49

$a = - 7$ $a=-7$

Begin by distributing $- 5$ $-5$ to each term of $(5 + 4 a)$ $(5+4a)$

$(- 5 \cdot 5) + (- 5 \cdot 4 a) = 115$ $(-5*5)+(-5*4a)=115$

$(- 25) + (- 20 a) = 115$ $(-25)+(-20a)=115$

$- 25 - 20 a = 115$ $-25-20a=115$

Add $25$ $25$ to both sides:

$- 25 + 25 - 20 a = 115 + 25$ $-25+25-20a=115+25$

$0 - 20 a = 140$ $0-20a=140$

$- 20 a = 140$ $-20a=140$

Divide both sides by $- 20$ $-20$

$cancel(-20)/cancel(-20)a=140/-20$

$a=-7$

How do you solve -5( 5+ 4a ) = 115−5(5+4a)=115-5( 5+ 4a ) = 115?