Question #2fa8b

1 Answer
Jane
Jan 25, 2018

#m# gm of water of specific heat #s# if suffers a temperature change of #theta# ,then heat(#H#) required is #m*s*theta#

Given, #m = 20 Kg# or #20000 gm#
S for water is 1 CGS unit
#theta = (95-15) = 80#

So, #H= 20000*1*80# Calorie or #1600000# Calorie

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