Question

Question #9ed21

Answer 1

`65 m/s`

Explanation:

Suppose,the ball was projected vertically with velocity `u`

So,distance(`s`) covered in `5th` second is `u- 1/2g(2*5-1)`

and, in `6th` second is `u-1/2g(2*6-1) = (h)`

Now,given,, `s=2h`

So, equating the obtained equations,we get, `u=(13g)/2`

Now,if `g= 10 m/s^2` ,then `u=65m/s`