("60.0 g Na"_2"SO"_4)/(1)*("1 mol Na"_2"SO"_4)/("142.04 g Na"_2"SO"_4) = "0.422 mol Na"_2"SO"_4
The "142.04 g/mol" came from getting the molar mass of "Na"_2"SO"_4 from the Periodic table.
Multiply across the top (60 * 1=60) and then divide by the bottom (1*142.04=142.04) to get 0.422 moles.