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Answer 1 · 2018-01-26T05:33:46

If #s# is the length of one side:

#f(s)=(2s^2+pis^2-10s+25)/pi#

Let s be the side length of one side:

The the amount of rope taken by the square is #4*s#, so the area length of the remainder of the string is #10-4s#.

The area of the square #=s^2#

The circumference(#C#) of the circle is #2*radius*pi#

#:. radius = C/(2pi)=(10-4s)/(2pi)=(5-2s)/pi#

Area of a circle #=pi*r^2=pi*((5-2s)/pi)^2=(2s^2-10s+25)/pi#

#:.# Total area #=(2s^2-10s+25)/pi+s^2=(2s^2+pis^2-10s+25)/pi#