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Question #b4350

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Jan 26, 2018

$6.25 \times 10^{18}$ $6.25 xx 10^18$ $e^{-}$ $e^-$

Explanation:

This involves unitary method.

1 $e^{-}$ $e^-$ has a charge of $1.6 \times 10^{- 19} C$ $1.6 xx 10^-19 C$

therefore , $1 C$ $1C$ charge has $\frac{1}{1.6 \times 10^{- 19}} e^{-}$ $1/(1.6 xx 10^-19) e^-$

which is $6.25 \times 10^{18}$ $6.25 xx 10^18$ $e^{-}$ $e^-$

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