Question

Question #e7d7a

Answer 1

`=500m` at an average velocity of `(250m)/(min)` towards the NW

Explanation:

To answer this, one should be guided by the following facts that a displacement;

1. is a straight line drawn from its original position to the object's final position.
2. is a vector quantity; thus give attention to the direction of motion, but if the direction is one-dimensional motion; direction can be represented as positive or negative. Take note of the following:
   `"upward (north)=positive; downward (south)=negative"`
   `"left (west)=negative; right (east)=positive"`
3. is not always equal to the distance being traveled.

This case, the car has traveled `300m" North(N)"`, `400m" West(W);,` and that, when we connect the initial position to its final position, apparently is forming a right triangle; thus, the
he concept of the Pythagorean Theorem can be applied to find the resultant length of the travel or its displacement.

`"Pythagoream theorem"` states that the square of the hypotenuse of a right triangle is equal to the squares of its legs; that is,

`c^2=a^2+b^2`

The length of the line that connects the final and initial positions of the car can be computed as;

`c=sqrt(a^2+b^2)`
where:

`c="the hypotenuse=the resultant length"`
`a="other leg=300m North"`
`b="other leg=400m West"`

`c=sqrt(300^2+400^2)`
`c=sqrt(90,000+160,000)`
`c=sqrt(250,000)`
`c=500m`

Therefore the displacement is `500m` at an average velocity of `(250m)/(min)` towards the `"Northwest"(NW)".`