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Question #ff1bb

1 Answer

Jan 27, 2018

$1.23 \frac{m}{s^{2}}$ $1.23m/s^2$

Explanation:

Acceleration is defined as change in the rate of velocity.

I.e $a = \frac{d v}{d t}$ $a= (dv)/(dt)$

Given, final velocity is $50 \frac{K m}{h r}$ $50 (Km)/(hr)$ or $13.89 \frac{m}{s}$ $13.89 m/s$

And,initial velocity is $10 \frac{K m}{h r}$ $10 (Km)/(hr)$ or $2.78 \frac{m}{s}$ $2.78 m/s$

And the time interval in which this change in velocity occurred is given as $9 s$ $9 s$

So,acceleration is $\frac{13.89 - 2.78}{9} \frac{m}{s^{2}}$ $(13.89-2.78)/9m/s^2$ or, $\approx 1.23 \frac{m}{s^{2}}$ $~~1.23 m/s^2$

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