How do you solve this system of equations? x+y+z=-1 2x+4y+z=1 x+2y-3z=-3

1 Answer
Jan 28, 2018

x= 2/7
y=-4/7
z=-5/7

Explanation:

x+y+z= -1
2x+4y+z= 1
x+2y+3z=-3

If you multiply the third equation by 2, you get:
2x+4y+6z= -6

Then you use that subtract second equation, which gives you
5z = -7
z = -5/7

Now, we kill off z from all the equations we get:
x+y = -2/7
2x+4y = 12/7
x+2y = -6/7

Now just use the third equation and minus the first one, you get:
y = -4/7

And plug back in the y and z values into x+y+z= -1, you will get:
x=2/7