How do you solve this system of equations? x+y+z=-1 2x+4y+z=1 x+2y-3z=-3

1 Answer
Jan 28, 2018

x= #2/7#
y=#-4/7#
z=#-5/7#

Explanation:

#x+y+z= -1#
#2x+4y+z= 1#
#x+2y+3z=-3#

If you multiply the third equation by 2, you get:
#2x+4y+6z= -6#

Then you use that subtract second equation, which gives you
#5z = -7#
z = #-5/7#

Now, we kill off z from all the equations we get:
#x+y = -2/7#
#2x+4y = 12/7#
#x+2y = -6/7#

Now just use the third equation and minus the first one, you get:
#y = -4/7#

And plug back in the y and z values into #x+y+z= -1#, you will get:
#x=2/7#