A projectile is shot at an angle of $(5pi)/12$ and a velocity of $1 m/s$ . How far away will the projectile land?

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Answer 1 · 2018-01-28T06:31:51

Range of projectile motion is expressed as $(u^2 sin (2theta)/g)$

Where $u$ is the velocity of projection and $theta$ is the angle of projection.

Given, $v=1 m"/"s$ and $theta= (5pi)/12$

So, putting in the values, we get the range is $0.05 m$ .

A projectile is shot at an angle of (5pi)/12 (5pi)/12 and a velocity of 1 m/s 1 m/s. How far away will the projectile land?