Question #49a3a

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Question #49a3a

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Answer 1 · 2018-01-29T17:46:28

$55 a^{2} + 24 a - 16$ $55a^2+24a-16$

Explanation:

If I understood you correctly you mean
${(7 a + a)}^{2} - {(- 4 + 3 a)}^{2}$ $(7a+a)^2-(-4+3a)^2$
otherwise feel free to correct me.
1. Calculate $7 a + a$ $7a+a$

$7 a + a = 8 a$ $7a+a=8a$

Square the brackets using the binomial formula

${(a + b)}^{2} = a^{2} + 2 a b + b^{2}$ $(a+b)^2=a^2+2ab+b^2$

${(8 a)}^{2} - {(3 a - 4)}^{2} = 8^{2} a^{2} - (3^{2} a^{2} - 4 \cdot 3 \cdot 2 a + 4^{2})$ $(8a)^2-(3a-4)^2=8^2a^2-(3^2a^2-4*3*2a+4^2)$

Simplify

$8^{2} a^{2} - (3^{2} a^{2} - 4 \cdot 3 \cdot 2 a + 4^{2}) = 64 a^{2} - 9 a^{2} + 24 a - 16 = 55 a^{2} + 24 a - 16$ $8^2a^2-(3^2a^2-4*3*2a+4^2)=64a^2-9a^2+24a-16=55a^2+24a-16$

Answer 2 · 2018-01-29T17:53:27

$- 2 a^{2} + 7 a + 4$ $-2a^2 +7a+4$

Explanation:

In the absence of any formatting, the meaning of the question is not clear. Here is another interpretation which I think is more likely because there is nothing to indicate that the given powers are for the whole expressions.

We have: second expression minus the first expression:

$(7 a + a^{2}) - (- 4 + 3 a^{2})$ $(7a+a^2) color(blue)(- (-4+3a^2))$

$= 7 a + a^{2} + 4 - 3 a^{2} \leftarrow$ $=7a+a^2 color(blue)(+4-3a^2)" "larr$ multiply out the bracket

$= - 2 a^{2} + 7 a + 4 \leftarrow$ $= -2a^2 +7a+4" "larr$ simplify the like terms.

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Question #49a3a

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