Question #ff514

1 Answer
turksvids
Jan 30, 2018

#lim_(x to oo) 31/e^x = 0#

Explanation:

If the problem is actually #lim_(x to oo) 31/e^x# then the answer is 0 because the numerator does not grow while the denominator grows without bound, so #lim_(x to oo) 31/e^x = 0#.

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