Question #c65e7

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Answer 1 · 2018-01-30T05:53:03

$= 44 g/mol$ $=44"g/mol"$

The condition of the gas is at STP, so that 1 mole of any ideal gas occupies a volume of 22.4L of that ideal gas is the mole relationship where a suitable conversion factor is obtainable from; i.e.,

$1 m o l of any ideal gas \equiv 22.4 L of any ideal gas$ $1mol " of any ideal gas"-=22.4L " of any ideal gas"$
Given the volume of the gas, convert it to mole. Take note also that $1 L = 1000 m L$ $1L=1000mL$ . Using the equivalence statements shown above, the value of the gas expressed in mole is;

$=112cancel(mL)xx(1cancel(L))/(1000cancel(mL))xx(1mol)/(22.4cancel(L))=0.005mol$
Now, find the variable $(Mm)$ as required in the problem. Plug in values as computed earlier. Thus,

$eta=(m)/(Mm)$
where:

$eta="number of moles"$
$m=mass$
$Mm="molar mass"$

$Mm=(m)/(eta)$
$Mm=(0.22g)/(0.005mol$
$Mm=44"g/mol"$