How do you solve ${log}_{5} x^{10} - {log}_{5} x^{2} = 39$ $\log _ { 5} x ^ { 10} - \log _ { 5} x ^ { 2} = 39$ ?

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Answer 1 · 2018-01-30T14:47:48

${log}_{5} x^{10} - {log}_{5} x^{2} = 39$ $log_5x^10−log_5x^2=39$

${log}_{5} x^{8} = 39$ $log_5x^8=39$

$x^{8} = 5^{39}$ $x^8=5^39$

$x = \pm 5^{\frac{39}{8}}$ $x=+-5^(39/8)$

How do you solve log5x10−log5x2=39\log _ { 5} x ^ { 10} - \log _ { 5} x ^ { 2} = 39?