Question

Question #89b68

Answer 1

`4Na + O_2-> 2Na_2O`

Mass of 1 mole of sodium is 22.99 g. Therefore, 9.5 g is equivalent to `9.5/22.99` moles., that is, 0.413 mole of sodium.

4 moles of Na require 1 mole of `O_2`.
0.413 mole of Na would therefore require `(1/4)*0.413` moles of `O_2`.

Solving this, we get,

0.1033 moles of oxygen is needed to completely react with 9.5 g of Na.