What is the energy in Joules of a single photon with wavelength of 154 nm?

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Answer 1 · 2018-01-31T13:05:22

#1.29077 * 10^-18##J#

You know,

#E = hcbar(nu) = (hc)/lambda# [Where h = Planck's constant,
c = velocity of electromagnetic radiation(light) and lambda = wavelength.]

So, just substitute every needed value.

So,

#E = ((6.626 * 10^-34) * (3 * 10^8) )/(154 * 10^-9)# Joules

#= 1.29077 * 10^-18# Joules.

Hence Explained.