A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 657 m/s. The gun is pointed directly at the center of the bull's-eye......?

A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 657 m/s. The gun is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.020 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?

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1 Answer
Jan 31, 2018

"please have a look at the solution below."

Explanation:

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  • friction and air resistance are ignored.
  • The bullet has done a freely falling motion from the point B to the point C..

BC=y=1/2 g t^2

0.02=1/2*9.81*t^2

t^2=(2*0.02)/(9.81)

t^2=(0.04)/(9.81)

sqrt(t^2)=sqrt((0.04)/(9.81))

  • the flying time of the bullet is:

t=0.02" "sec

AB=v*t

AB=657*0.02=13.14" "meters.