Question

Question #02f6e

Answer 1

`="60.15g " MgSO_4`

Explanation:

1. Find the molar mass of `MgSO_4` which relative atomic masses of elements constituting the compound is obtainable in the periodic table.
   `=120" g/mol"`
2. Given the concentration of the solution, and the assumed volume, the number of moles `(eta)` of the solute can be computed as described below;
   `M=eta/V`; rearrange formula and isolate `eta`
   `eta=MxxV`

`where:`

`M=Molarity=0.5M=0.5" mol/L"`
`V=Volume=1L`

`eta=MV`
`eta=(0.5mol)/cancel((L))xx1cancel(L)`
`eta=0.5molMgSO_4`

1. Now, use the molar mass of the compound to find the mass of the solute; i.e.,
   `=0.5molcancel(MgSO_4)xx(120.3gMgSO_4)/(1cancel(molMgSO_4))`
   `=60.15gMgSO_4`