Question #82928

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Answer 1 · 2018-02-01T03:46:36

$= 0.52 m o l C O_{2}$ $=0.52molCO_2$

Write and balance the equation.
$2 C_{4} H_{10} + 13 O_{2} \to 8 C O_{2} + 10 H_{2} O$ $2C_4H_10+13O_2->8CO_2+10H_2O$
Given the mass of $O_{2}$ $O_2$ , convert this value to mole through molar conversion using the molar mass of $O_{2}$ $O_2$ as conversion factor; i.e.,
$=27cancel(gO_2)xx(1molO_2)/(32cancel(gO_2))$
$=0.84375molO_2~~0.84molO_2$
With reference to the balanced equation for the mole ratio of $O_2$ and $CO_2$ , find the mole value of $CO_2$ through molar conversion.
$=0.84cancel(molO_2)xx(8molCO_2)/(13cancel(molO_2))$
$=0.52molCO_2$