Question

Question #c0970

Answer 1

`1.63 "mol"` of sodium chloride.

Explanation:

Remember that the formula for moles, `n`, is `n=m/M`, where `m` is the mass of the substance, and `M` its molar mass.

Therefore, we must first calculate the mass of `NaCl` present.

To do this, we can use the formula for density, `rho`, when `rho=m/V`, where `V` is the volume of liquid.

The density of sodium chloride is `2.16g/(mL)`.

So input: `2.16=m/44`

`2.16*44=m/44*44`

`m=95.04g` of sodium chloride.

Now we may use `n=m/M`.

The molar mass of sodium chloride is `58.4g/("mol")`.

So simply input: `n=95.04/58.4`

`n=1.63 "mol"` of sodium chloride.

Answer 2

`~~1.63mol`

Explanation:

Well, we'll need a few steps here...

First, know that `1mL=1cm^3`, so

`44mL=44cm^3`

Now, we can use the density equation to find the mass of the sodium chloride:

`rho=m/V` or `m=rho*V`

The density of sodium chloride is `2.16g"/"cm^3`

`:."mass"=2.16g"/"cm^3*44cm^3=95.04g`

So, we have `95.04g` of sodium chloride.

Next, we have to use the molar mass formula to find the amount of moles.

`"moles"="mass"/"molar mass"`

The molar mass of sodium chloride is `58.4g"/"mol`.

`:."moles"=(95.04cancelg)/(58.4cancelg"/"mol)~~1.63mol`

So, our final answer is `1.63` moles of sodium chloride.