Question

Question #763da

Answer 1

See below...

Explanation:

Firstly, I would get the line equation in the

`y=mx+c` format.

`therefore 3y= 2x-6`

`y = (2/3)x - 2`

Now I would make a table of values ranging from the `x` values `-3` to `3`

Each `x` value corresponds to a `y` value giving you a set of coordinates.

E.g when `x =3`, `y=(2/3)(3)-2=0`
`therefore (3,0)`

After getting these coordinates, plot these points on a four quadrant axis and finish with a smooth, straight line. graph{-2x+3y=-6 [-10, 10, -5, 5]}