Question #91b45

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Question #91b45

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Answer 1 · 2018-02-02T16:12:11

$9.41$ $9.41$ x $10^{21}$ $10^21$ molecules

Explanation:

$16$ $16$ grams of Oxygen atom = $1$ $1$ mole
$1$ $1$ mole = $6.023$ $6.023$ x $10^{23}$ $10^23$ molecules
$16$ $16$ grams of Oxygen atom have molecules = $6.023$ $6.023$ x $10^{23}$ $10^23$ molecules
$0.25$ $0.25$ g of Oxygen atom will have molecules = ( $6.023$ $6.023$ x $10^{23}$ $10^23$ molecules) x $0.25$ $0.25$ g]/ $16$ $16$ g = $9.41$ $9.41$ x $10^{21}$ $10^21$ molecules

OR
Oxygen = $0.25$ $0.25$ g
molar mass = $16$ $16$ g
no. of moles = $\frac{0.25}{16}$ $0.25/16$ = 0.0156 moles

$1$ $1$ mole = $6.023$ $6.023$ x $10^{23}$ $10^23$ molecules
so, $0.0156$ $0.0156$ moles of Oxygen atom = $0.0156$ $0.0156$ moles x $6.023$ $6.023$ x $10^{23}$ $10^23$ molecules = $9.39$ $9.39$ x $10^{21}$ $10^21$ molecules = $9.4$ $9.4$ x $10^{21}$ $10^21$ molecules

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Question #91b45

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