What is the distance between the following polar coordinates?: # (8,(-21pi)/12), (5,(-3pi)/8) #

1 Answer
Feb 2, 2018

#10.937#

Explanation:

First #(8,-(21pi)/12)# can be simplified a bit #(8, -(7pi)/4)#, and since #-(7pi)/4# is coterminal to #pi/4#, we'll use #(8,pi/4)# as an equivalent point. The other point we'll keep as #(5,-(3pi)/8)#.

If we plot the points and use them as two vertices of a triangle with the origin as the third vertex, we have sides 8 and 5 with an angle of #pi/4 + (3pi)/8 = (5pi)/8# between them.

For this triangle we can use the Law of Cosines to find the side opposite #(5pi)/8#, which is the distance between the given points:

#c=sqrt(a^2+b^2-2abcos(C))#

#c=sqrt(8^2+5^2-2(8)(5)cos((5pi)/8))#

#c approx 10.937#

This video might also be helpful.