Question #1830f

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Question #1830f

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Answer 1 · 2018-02-03T03:16:22

$73 g$ $73g$

Explanation:

The formula for density, where density is $ρ$ $rho$ , is $ρ = \frac{m}{V}$ $rho=m/V$ .

$m$ $m$ is the mass, and $V$ $V$ the volume.

The formula can be rearranged as: $m = ρ V$ $m=rhoV$ .

So for liquid A:

$m = ρ V$ $m=rhoV$

$m = 1.44 \cdot 25$ $m=1.44*25$

$m = 36 g$ $m=36g$

For liqiud B:

$m = ρ V$ $m=rhoV$

$m = 1.48 \cdot 25$ $m=1.48*25$

$m = 37 g$ $m=37g$

We have $36 g$ $36g$ of one liquid and $37 g$ $37g$ of the other.

Totally, we have $36 + 37 = 73 g$ $36+37=73g$ of liquid.

Answer 2 · 2018-02-03T04:23:40

$= 73 g$ $=73g$

Explanation:

This can be solved using the density formula; i.e.,

$m = ρ \times V$ $m=rhoxxV$
where:

$m = mass expressed in g$ $m="mass expressed in g"$
$ρ = density expressed in g/ml$ $rho="density expressed in g/ml"$
$V = volume expressed in mL$ $V="volume expressed in mL"$
Assuming that the liquids are miscible, the mass of the liquids in the flask is computed as follows:

$m_{t} = m L i q u i d_{A} + m L i q u i d_{B}$ $m_t=mLiquid_A+mLiquid_B$

$m_{t} = ((ρ_{A}) (V_{A}) + (ρ_{B}) (V_{B}))$ $m_t=((rho_A)(V_A)+(rho_B)(V_B))$

$m_t=((1.44g)/cancel(ml)xx25cancel(ml))+((1.48g)/cancel(ml)xx25cancel(ml))$

$m_t=36g+37g$

$m_t=73g$

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Question #1830f

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