Question #905ff

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Question #905ff

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Answer 1 · 2018-02-06T14:06:48

$$ 8526.2$ $$8526.2$

Explanation:

Cost of the fees in 1981= $$ 4790$ $$4790$
Rise in fees= $78 %$ $78%$
Hence, new amount= $4790 + (\frac{78}{100} \cdot 4790)$ $4790+(78/100 *4790)$
= $4790 + 3736.2$ $4790+3736.2$
= $$ 8526.2$ $$8526.2$
Hence the fees was $$ 8526.2$ $$8526.2$ in 1995.

Answer 2 · 2018-02-06T14:09:20

$$ 8526 to nearest dollar$ $$8526" to nearest dollar"$

Explanation:

$let $ 4790 be 100 %$ $"let "$4790" be "100%$

$then 100 + 78 = 178 % = \frac{178}{100} = 1.78$ $"then "100+78=178%=178/100=1.78$

$multiplying the original cost by this factor gives the cost$ $"multiplying the original cost by this factor gives the cost"$
$in 1995$ $"in 1995"$

$cost in 1995 = $ 4790 \times 1.78 = $ 8526.20$ $"cost in 1995 "=$4790xx1.78=$8526.20$

$\approx $ 8526 to nearest dollar$ $~~$8526" to nearest dollar"$

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Question #905ff

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