What is the volume of the solid produced by revolving f(x)=x^3, x in [0,3] around y=-1?
1 Answer
Feb 7, 2018
See explanation below
Explanation:
We have a revolution solid with a hole inside because the spin axis is y=-1.
Consider a volume element with a width of
So, the volume of this volume element is
The sbstitution in that formula give us:
Integrating between 0 and 3 wil give us the volume requested
solving this integral we have: