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Answer 1 · 2018-02-07T14:21:28

44%

#K= 1/2m^2 =(mv)^2/(2m)=p^2/(2m)#

#p= mv#

A 20% increased from #p_0# means that

#p=1.2p_0#

#K= (1.2p_0)^2/(2m) =1.44 p_0^2/(2m)=1.44K_0#

#(K-K_0)/K_0#=1.44-1=0.44=44%

Hence, Kinetic energy increased by 44%