How many grams of silicon are in a computer chip with 1.08 x 10^23 atoms of Si?

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Answer 1 · 2018-02-07T19:32:53

Mass of Silicon is 5.0 grams in a computer chip.

Given:
Number of Atoms Of silicon = $1.08*10^23$
Avogadro number = $6.023*10^23$
Molar Mass of Silicon = $28.09$ g/mol

Required:
Mass of silicon in computer chip = ?

Using Formula:
Number of moles(n) = number of atoms(N)/ Avogadro Number(Na)

$n$ = $1.08*10^23$ / $6.023*10^23$

$n$ = $0.17$ moles

Now applying second formula for calculating Mass of silicon;

Number of moles = mass of silicon / Molar mass of silicon

n = $m / M$

By Cross multiplication;

$m = n * M$

Now apply moles $(n)$ of silicon value here;

$m = 0.17mol * 28.09$ g / mol

m = 5.0 g.

Hope this Helps.. ^_^

Answer 2 · 2018-02-07T19:40:55

Well, we need to have TWO pieces of data....I get about $5*g$ ..

$1.$ $"One mole of silicon has a mass of 28.09 g."$

$2.$ $"One mole of silicon contains "6.022xx10^23*"atoms".$

And with these data we can equate MASS with the number of atoms...and this is the principle of chemical equivalence....

And so we take the product of the quotient....

$(1.08xx10^23*"silicon atoms")/(6.022xx10^23*"silicon atoms"*mol^-1)xx28.09*g*mol^-1$

$=??*g$