Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

Question #5db68

1 Answer

Feb 8, 2018

The formula is $C O_{2}$ $CO_2$ and the mass is 673.9 g.

Explanation:

$6.02 \times 10^{23}$ $6.02xx10^(23)$ particles of substance is known as a mole of that substance. This number is known as Avogadro's constant.

So, if we divide the given amount by $6.02 \times 10^{23}$ $6.02xx10^(23)$ , we have the number of moles of carbon dioxide, $C O_{2}$ $CO_2$ .

$9.22 \times 10^{24} \div 6.02 \times 10^{23} = 15.316$ $9.22xx10^(24)-:6.02xx10^(23)=15.316$ moles

The mass of one mole of $C O_{2}$ $CO_2$ is 44.0 g (based on the atomic masses of carbon (12) and oxygen (16)).

$15.316 mol \times 44.0 \frac{g}{mol} = 673.9 g$ $15.316 "mol" xx 44.0 g/"mol" = 673.9 g$

Related questions

Impact of this question

805 views around the world

You can reuse this answer
Creative Commons License