Question #5e126

1 Answer
Alim K. ยท Jumbotron
Feb 8, 2018

0.9139 liters

Explanation:

Mass of C_6H_12O_6 = 72 + 12 + 64 = 148 gmol^-1

Mole of glucose rArr (1g)/(148gmol^-1) = 0.0068mol of Glucose

Mole ratio between glucose and water is 1:6

Then; water is 0.0068 xx 6 = 0.0408 mol of water

Volume of water is 0.0408mol xx (22.4 L)/(1mol) = 0.9139 L

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