How to solve? Help please!

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Answer 1 · 2018-02-08T18:42:16

$"See the description section for details."$

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First we must calculate the system's capacity.
The capacitors are connected in series.
We can calculate the equivalent capacitance of series-connected capacitors using the formula given below.

$C=(C_1*C_2)/(C_1+C_2)$

$C=(6*3)/(6+3)=18/9=2 mu F$

$2 mu F=2*10^-6 F$

$Q=C*V$

$"where;"$

$Q:"charge stored in system"$

$V:10V$

$C=2*10^-6 F$

$Q=2*10^-6*10=2*10^-5 C$

The amount of charge stored by the series connected capacitors is equal.
The electric charge of each of the series-connected capacitors is equal to the electric charge of the system.

$"charge stored on "C_1:2*10^-5 C$

$"charge stored on "C_2:2*10^-5 C$

$"charge stored on system "C:2*10^-5 C$

In the second circuit we see that the poles have changed. The capacitors are connected in parallel.

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Since the voltages of parallel-connected capacitors are equal, it is necessary to make a charge transfer between the capacitors.

-The new charge distribution is as follows.

$"if charge of "C_2=x$

$"then charge of "C_1=2x$

$x+2x="system's charge"$

$3x=2*10^-5$

$x=2/3*10^-5C" charge of "C_2$

$2x=2*2/3*10^-5=4/3 *10^-5C" charge of C_1"$