Question #f6379

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Question #f6379

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Answer 1 · 2018-02-09T07:56:34

See explanation.

Explanation:

$\frac{d}{d x} (\frac{1}{\sqrt{x}}) = \frac{d}{d x} (x^{- \frac{1}{2}}) = - \frac{1}{2} x^{- \frac{1}{2} - 1}$ $d/dx(1/sqrt(x))=d/dx(x^(-1/2))=-1/2x^(-1/2-1)$

$- \frac{1}{2} \cdot (x^{- \frac{3}{2}}) = - \frac{1}{2} \cdot \frac{1}{\sqrt{x^{3}}} = - \frac{1}{2 \sqrt{x^{3}}}$ $-1/2*(x^(-3/2))=-1/2*1/sqrt(x^3)=-1/(2sqrt(x^3))$

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Question #f6379

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